Q.

An area of cross-section of rubber string is  2 cm2. Its length is doubled when stretched with a linear force of 2×105 dynes. The Young's modulus of the rubber in  dyne/cm2 will be

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a

4×105

b

1×105

c

1×104

d

2×105

answer is B.

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Detailed Solution

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If length of the wire is doubled then strain = 1

Y= Stress = Force  Area =2×1052=105 dyne cm2

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An area of cross-section of rubber string is  2 cm2. Its length is doubled when stretched with a linear force of 2×105 dynes. The Young's modulus of the rubber in  dyne/cm2 will be