An aromatic compound ‘A’ on heating with $$Br2$$ and KOH forms a compound ‘B’ of molecular formula $$C6H7N$$ which on reacting with $$CHCl3$$ and alcoholic KOH produces a foul smelling compound ‘C’. Write the structures and IUPAC names of compounds A, B and C.

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Infinity Learn · Accepted Answer

When benzamide reacts with $$Br2/KOH$$ and Hoffmann bromamide degradation reaction will take place to form aniline and when aniline is treated with $$CHCl3/KOH$$, carbylamine reaction will take place to form phenyl isocyanide.Therefore, A $$=$$ Benzamide, B $$=$$ Aniline, and C $$=$$ Phenyl Isocyanide

An aromatic compound ‘A’ on heating with Br₂and KOH forms a compound ‘B’ of molecular formula C₆H₇N which on reacting with CHCl₃ and alcoholic KOH produces a foul smelling compound ‘C’. Write the structures and IUPAC names of compounds A, B and C.

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An aromatic compound ‘A’ on heating with Br2 and KOH forms a compound ‘B’ of molecular formula C6H7N which on reacting with CHCl3 and alcoholic KOH produces a foul smelling compound ‘C’. Write the structures and IUPAC names of compounds A, B and C.

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

An aromatic compound ‘A’ on heating with Br₂and KOH forms a compound ‘B’ of molecular formula C₆H₇N which on reacting with CHCl₃ and alcoholic KOH produces a foul smelling compound ‘C’. Write the structures and IUPAC names of compounds A, B and C.