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An arrangement setup inside a lift is shown in the figure. The pulleys and threads are ideal and masses of the blockd are m and M(M>2m).Find minimum acceleration of the lift for which the thread remains taut and both the blocks accelerate in the same direction relative to the ground. Acceleration due to gravity is g.

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$\frac{(M - 2 m) g}{5 m}$

$\frac{(M - 2 m) 5 g}{6 m}$

$\frac{(M - 2 m) g}{6 m}$

$\frac{(M - m) g}{6 m}$

answer is A.

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Detailed Solution

An arrangement setup inside a lift is above the pulleys are threads are ideal and masses of blocks are m and M(M>2m).

Minimum acceleration

$a > \frac{(M - 2 m) g}{6 m}$

Hence the correct option is 1

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