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Q.

An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of escape velocity from the earth. The height of the satellite above the earth's surface will be : 

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a

6000 km

b

5800 km

c

7500 km

d

6400 km

answer is D.

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Detailed Solution

v0=12ve⇒GMr=122GMR
r=2R→ h = r - R = R = 6400km

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