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An artificial satellite is placed into a circular orbit around earth at such a height that it always remains above a definite place on the surface of earth. Its height from the surface of earth is

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6400 km

4800 km

32000 km

36000 km

answer is D.

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Detailed Solution

${mrω}^{2} = \frac{GMm}{r^{2}} r = R + h = {(\frac{{GMT}^{2}}{4 π^{2}})}^{1 / 3} T = 24 h R = 6400 k m G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}$

Substituting the values we get

$h = 36000 km$ (approx)

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