An artificial satellite moves in a circular orbit around the earth. Total energy of the satellite is given by E. The potential energy of the satellite is 

We know that, the potential energy of the satellite,

$U=-\frac{G{M}_{e}m}{R_e}$

The kinetic energy of the satellite,   $K=\frac{1}{2}\frac{G{M}_{e}m}{R_e}$

The total energy,  $E=U+K=-\frac{G{M}_{e}m}{R_e}+\frac{1}{2}\frac{G{M}_{e}m}{R_e}=-\frac{1}{2}\frac{G{M}_{e}m}{R_e}$

$\Rightarrow 2E=-\frac{G{M}_{e}m}{R_e}\Rightarrow -2E=U$

So, potential energy =  2 (total energy)

$\Rightarrow \mathrm{PE}=2E$