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An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length $⨍$ oof the objective and the focal length $⨍$ eof the eyepiece are

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45 cm and – 9 cm

– 7.2 cm and 5 cm

50 cm and 10 cm

30 cm and 6 cm

answer is D.

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Detailed Solution

$. (d) For telescope, |m| = \frac{|⨍_{0}|}{|⨍_{e}|} = 5 and length of the telescope, L = |⨍_{0}| + |⨍_{e}| = 36 From Eqs . (i) and (ii), we get \Rightarrow ⨍_{e} =6 cm and ⨍_{0} =30 cm$

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