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An athlete in the Olympic Games covers a distance of 200 m in 20 s. His kinetic energy can be estimated to be in the range

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$2, 000 J - 5, 000 J$

200J-500J

$20, 000 J - 50, 000 J$

$2 \times 10^{5} J - 3 \times 10^{5} J$

answer is D.

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Detailed Solution

$KE = \frac{1}{2} {mv}^{2}$

$v = \frac{s}{t} = \frac{200}{20} = 10 m / s$

Assuming avg weight to be 40kg to 100kg

Average kinetic energy is

$K = 2000 J - 5000 J$

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