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Q.

An athlete is given 100g of glucose (C6H12O6) for energy. This is equivalent to 1800kJ of energy. The 50% of this energy gained is utilized by the athlete for sports activities at the event. In  order to avoid storage of energy, the weight of extra water he would need to perspire is______g (Nearest integer)
Assume that there is no other way of consuming stored energy.
Given: The enthalpy of evaporation of water is 45 kJ  mol-1
Molar mass of C, H & O are 12,1 and 16 g mol-1 .

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answer is 360.

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Detailed Solution

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1 mole 45KJ?900KJ900×145×18=360 gms

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An athlete is given 100g of glucose (C6H12O6) for energy. This is equivalent to 1800kJ of energy. The 50% of this energy gained is utilized by the athlete for sports activities at the event. In  order to avoid storage of energy, the weight of extra water he would need to perspire is______g (Nearest integer)Assume that there is no other way of consuming stored energy.Given: The enthalpy of evaporation of water is 45 kJ  mol-1Molar mass of C, H & O are 12,1 and 16 g mol-1 .