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An average force of 125 N is applied on a machine gun firing bullets each of mass 10 g at the speed of 250 m/s to keep it in position. The number of bullets fired per second by the machine gun is:

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answer is D.

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Detailed Solution

$F = 125 N$
$m = 10 \times 10^{- 3} kg = 10^{- 2} kg;$
$v = 250 m / s$
$F = \frac{NmV}{t}$

$\Rightarrow \frac{N}{t} = \frac{F}{mV} = \frac{125}{10^{- 2} \times 250} = 50$

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