An azeotropic mixture of water(b.pt=1000c) and HCl (b.pt = 850C) boils at 108.50c. When this mixture is distilled, it is possible to obtain

Neither HCl nor H 2 O in pure state

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

An azeotropic mixture of water(b.pt=100⁰c) and HCl (b.pt = 85⁰C) boils at 108.50c. When this mixture is distilled, it is possible to obtain

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Pure water

Neither HCl nor H₂O in pure state

Pure HCl

Both HCl & water

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

BP of H₂O = 100^oc

BP of HCl = 85^oc

BP of (HCl+H₂O) azeotrope = 108.5^oc

It is a maximum boiling azeotrope

It is not possible to separate the components of an azeotrope

Because both the components boil at same temperature

An azeotrope is a constant boiling mix.

$\therefore$ neither HCl nor H₂O can be obtained in pure state by fractional distillation

JEE

NEET

Foundation JEE

Foundation NEET

CBSE