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An ebonite rod, when rubbed with wool, acquires a negative charge of 4.0 $\times 10^{- 9} C .$ How many free electrons can constitute this much charge?

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2 \times 10^{- 9}

2.5 \times 10^{10}

4.0 \times 10^{- 9}

None of these

answer is B.

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Detailed Solution

An ebonite rod, when rubbed with wool, acquires a negative charge of

4.0 \times 10^{- 9} C

. Then

2.5 \times 10^{10}

number of free electrons can constitute this much charge.
Here, Charge on ebonite rod,

Q = - 4.0 \times 10^{- 9} C

and charge on an electron,

e = - 1.60 \times 10^{- 19} C

Therefore we get, Number of free electrons in ebonite rod,

n = \frac{Q}{e}

\Rightarrow n = \frac{- 4.0 \times 10^{- 9}}{- 1.60 \times 10^{- 19}}

\Rightarrow n = 2.5 \times 10^{10} .

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