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Q.

An elastic string of constant k is attached to a block of mass m as shown. The block is given an extension of 2mgkfrom the equilibrium position and released. The time period of oscillations of the block is

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a

2πmk

b

4mkπ3+3

c

2πmk+23mk

d

πmk+3mk

answer is B.

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Detailed Solution

Here string becomes slack when acceleration of body becomes more than g above equilibrium position. Hence during that period, SHM disappears:

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upto P3 , SHM appears and between P3 & P4 , SHM disappears. =2T13+tP3P4+tP4P3

T=tOP2+tP2O+tOP3+tP3P4+tP4P3+tP3O

 where :T1=2πmk velocity at P3 is : 

v=ωA2x2=ω4b2b2=bω3

tP3P4+tP4P3=2vg

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