An electric bulb is connected to a 500 V generator. The current flowing through the bulb is 0.2 A. What must be the power of the bulb?

 

Electrical power is the rate at which electrical energy is consumed per unit of time.

$\text{P=}\frac{\mathrm{W}}{\mathrm{t}}=\mathrm{VI}={\mathrm{I}}^2\mathrm{R}=\frac{{\mathrm{V}}^2}{\mathrm{R}}$

Where V= Potential difference, R= Resistance, and I= current.

Given - Potential difference V= 500 V and current I= 0.2 A

Electric power can be written as,

$\text{P=VI}$

$\text{P=500×0.2=100 W}$

Hence, 100W is the correct answer.