Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

An electric bulb is rated $220 V$ and $100 W$ . When it is operated on $110 V$ , the power consumed by the bulb is [[1]] $W$ .

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

An electric bulb is rated

220 V

and

100 W

. When it is operated on

110 V

, then the power consumed by the bulb is

25 W

.
Given,
Voltage of the electric bulb

(V) = 220 V

………….. (i)
Power of the electric bulb

(P) = 100 W

……………. (ii)
We know that

P = \frac{V^{2}}{R}

So, the resistance of the bulb

(R) = \frac{V^{2}}{P} = \frac{220 \times 220}{100}

Now put the values of equations (i) and (ii) in equation (iii) we get,

R = \frac{220 \times 220}{100}

R = 484 Ω

………………. (iv)
Now when the bulb connected to

110 V

then the power consumed (P’) is,

P' = \frac{V^{2}}{R}

…………………. (v)
Now put the value of equation (iv) in equation (v)

P' = \frac{110 \times 110}{484}

P' = \frac{12100}{484}

P' = 25 W

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!