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An electric bulb rated for 500 watts at 100 volts is used in a circuit having a 200-volt supply. The resistance R that must be put in series with the bulb, so that the bulb draws 500 watts is

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10 $Ω$

20 $Ω$

50 $Ω$

100 $Ω$

answer is B.

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Detailed Solution

$R_{b} = \frac{100 \times 100}{500} = 20 Ω$
Hence a resistance of 20 $Ω$ is needed in series for the bulb to draw 500 W.

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