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An electric bulb rated for $500 W$ at $100 V$ is used in a circuit having a $200 V$ supply. The resistance $R$ that must be put in series with the bulb, so that the bulb delivers $500 W$ is ......

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Detailed Solution

Resistance of the given bulb

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$R_{b} = \frac{V^{2}}{P} = \frac{(100)^{2}}{500} = 20 Ω$

If the bulb delivers 500 w in the supply 200 volt new resistance = $\frac{200 \times 200}{500} = 80 o h m$

80 = 20 + x

so x = 60 ohm

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An electric bulb rated for 500W at 100 V is used in a circuit having a 200 V supply. The resistance R that must be put in series with the bulb, so that the bulb delivers 500W is ......