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An electric cable of copper has just one wire of radius 9 mm. Its resistance is $14 Ω .$ If this single copper wire of the cable is replaced by seven identical well insulated copper wires each of radius 3 mm and of same length connected in parallel, then the new resistance of the combination will be

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$28 Ω$

$18 Ω$

$9 Ω$

$126 Ω$

answer is B.

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Detailed Solution

$R = \frac{ρ l}{A}$

$\frac{R_{2}}{14} = \frac{9^{2}}{7 (3)^{2}} \Rightarrow R_{2} = 18 Ω$

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