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An electric current passes through non-uniform cross-section wire made of homogeneous and isotropic material. If $j_{A}$ and $j_{B}$ are the current densities and $E_{A}$ and $E_{B}$ ate the electric field intensities at A and ,B respectively, then

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$j_{A} > j_{B}; E_{A} > E_{B}$

$j_{A} > j_{B}; E_{A} < E_{B}$

$j_{A} < j_{B}; E_{A} > E_{B}$

$j_{A} < j_{B}; E_{A} < E_{B}$

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{I}{A} = j and j = \frac{E}{ρ} \\ ∴ j_{A} > j_{B} and E_{A} > E_{B} \end{array}$

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