An electric dipole is along a uniform electric field. If it is deflected by ${60}^0$, work done by agent is $2\times {10}^{-19} \mathrm{J}$. Then the work done by an agent if it is deflected by ${30}^0$  further is

Given data: Electric dipole placed in a uniform electric field

Concept used: Electric dipole

Detailed solution:

The work done on the dipole when deflected by an angle of 60⁰ is given by

$W=-PE\cos {60}^0=-2\times {10}^{-19}J$

Now, the work done in deflecting the dipole by another 30⁰ is given by

$W_2=-PE\cos {90}^0=0$

Therefore, the total work done is given by

$W=W_2-W_1$

$W=0-\left(-2\times {10}^{-19}\right)$

$W=2\times {10}^{-19}J$