Q.

An electric dipole is along a uniform electric field. If it is deflected by 600, work done by agent is 2×10-19 J. Then the work done by an agent if it is deflected by 300  further is

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a

4×10-19 J

b

2.5×10-19 J

c

2×10-16 J

d

2×10-19 J

answer is B.

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Detailed Solution

Given data: Electric dipole placed in a uniform electric field

Concept used: Electric dipole

Detailed solution:

The work done on the dipole when deflected by an angle of 600 is given by

W=-PEcos600=-2×10-19J

Now, the work done in deflecting the dipole by another 300 is given by

W2=-PEcos900=0

Therefore, the total work done is given by

W=W2-W1

W=0--2×10-19

W=2×10-19J

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