An electric dipole is along a uniform electric field. If it is deflected by $60^{0}$ , work done by agent is $2 \times 10^{- 19} J$ . Then the work done by an agent if it is deflected by $30^{0}$ further is

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$2.5 \times 10^{- 19} J$

$2 \times 10^{- 19} J$

$4 \times 10^{- 19} J$

$2 \times 10^{- 16} J$

answer is B.

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Detailed Solution

Given data: Electric dipole placed in a uniform electric field

Concept used: Electric dipole

Detailed solution:

The work done on the dipole when deflected by an angle of 60⁰ is given by

$W = - P E \cos 60^{0} = - 2 \times 10^{- 19} J$

Now, the work done in deflecting the dipole by another 30⁰ is given by

$W_{2} = - P E \cos 90^{0} = 0$

Therefore, the total work done is given by

$W = W_{2} - W_{1}$

$W = 0 - (- 2 \times 10^{- 19})$

$W = 2 \times 10^{- 19} J$

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