An electric dipole is placed as shown in the figureThe electric potential (in 102 V) at a point P due to the dipole is 14πε0=k and ε0=permittivity of free space)

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An electric dipole is placed as shown in the figure
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The electric potential (in $10^{2} V$ ) at a point P due to the dipole is $(\frac{1}{4 {πε}_{0}} = k and ε_{0} =$ permittivity of free space)

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(5/8) qk

(8/5) qk

(8/3) qk

(3/8) qk

answer is D.

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Detailed Solution

$\begin{array}{l} V = V_{1} + V_{2} \\ ∴= \frac{1}{4 {πε}_{0}} [\frac{+ q}{r_{1}} + \frac{- q}{r_{2}}] \\ = Kq [\frac{1}{2 \times 10^{- 2}} - \frac{1}{8 \times 10^{- 2}}] \\ = (\frac{3}{8}) \times 10^{2} kq \end{array}$