An electric dipole is placed at an angle of 30° with an electric field intensity 2 × 10⁵N/C. It experiences a torque equal to 4 N.m. The charge on the dipole, if the dipole length is 2cm, is

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5mC

7mC

8mC

2mC

answer is B.

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Detailed Solution

$\begin{array}{l} Torque C = PEsin θ; 4 = P (2 \times 10^{5}) \sin 30^{0} \\ P = 4 \times 10^{- 5}; q \times 2 a = 4 \times 10^{- 5} \\ q = \frac{4 \times 10^{- 5}}{2 \times 10^{- 2}} = 2 \times 10^{- 3} C = 2 mc \end{array}$

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