An electric dipole is placed at an angle of 300 with an electric field of intensity 2 × 105 NC-1. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

τ=(q×2l)Esin⁡θq=τ2lxEsin⁡θ

An electric dipole is placed at an angle of 300 with an electric field of intensity 2 × 105 NC-1. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

τ=(q×2l)Esin⁡θq=τ2lxEsin⁡θ

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An electric dipole is placed at an angle of 30⁰ with an electric field of intensity 2 × 10⁵ NC^-1. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

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$\begin{array}{l} τ = (q \times 2 l) Esin θ \\ q = \frac{τ}{2 lxEsin θ} \end{array}$

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An electric dipole is placed at an angle of 300 with an electric field of intensity 2 × 105 NC-1. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

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An electric dipole is placed at an angle of 30⁰ with an electric field of intensity 2 × 10⁵ NC^-1. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.