An electric dipole is placed at the origin O and is directed along the x-axis. At a point P, far away from the dipole, the electric field is parallel to y-axis. OP makes an angle $θ$ with the x-axis, then

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$θ = 45 °$

$tanθ = \sqrt{2}$

$tanθ = \sqrt{3}$

$tanθ = \frac{1}{\sqrt{2}}$

answer is B.

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Detailed Solution

We know that in this case electric field makes an angle $θ$ + a with the direction of dipole.

$Also, tanα = \frac{1}{2} tanθ Here, θ + α = 90 ° \Rightarrow α = 90 ° - θ Hence \tan (90 ° - θ) = \frac{1}{2} tanθ \Rightarrow cotθ = \frac{1}{2} tanθ \Rightarrow \tan^{2} θ = 2 \Rightarrow tanθ = \sqrt{2}$

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