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Q.

An electric dipole is placed in a uniform electric field $\vec{E}$ of magnitude $40 N C^{- 1} .$ Graph shows the magnitude of the torque on the dipole versus the angle $θ$ between the field $\vec{E}$ and the dipole moment $\vec{p} .$ The magnitude of dipole moment $\vec{p}$ is equal to

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a

$5.0 \times 10^{- 28} C m$

b

$1.25 \times 10^{- 28} C m$

c

$2.0 \times 10^{- 25} C m$

d

$2.5 \times 10^{- 28} C m$

answer is C.

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Detailed Solution

$\vec{τ} = \vec{p} \times \vec{E} o r τ_{\max} = p E$

or $50 \times 10^{- 28} = p 40 o r p = 1.25 \times 10^{- 28} C m$

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An electric dipole is placed in a uniform electric field E→ of magnitude 40 NC−1.Graph shows the magnitude of the torque on the dipole versus the angle θ between the field E→ and the dipole moment p→. The magnitude of dipole moment p→ is equal to