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Q.

An electric dipole moment p=(2.0i^+3.0j^) μC . It is placed in a uniform electric field E=(3.0i^+2.0k^)×105NC1

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a

The potential energy of the dipole is – 0.6J

b

If the dipole is rotated in the electric field, the maximum potential energy of the dipole is 1.3J

c

The potential energy of the dipole is 0.6J

d

The torque that E  exerts on p  is (0.6i^0.4j^0.9k^)  Nm

answer is Ü.

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Detailed Solution

P=(2i+3j)106andE=(3i+2k)105

τ¯=P¯×E¯=(0.6i0.4j0.9k)U=P.E=2×3×101=0.6Umax=|P||E|=13×13×101=1.3J

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