Q.

An electric dipole moment p=(2.0i^+3.0j^)μC is placed in a uniform electric field,E=(3.0i^+2.0k^)×105NC1

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a

The potential energy of the dipole is –0.6 J.

b

The torque that E exerts on P is (0.6i^0.4j^0.9k^)Nm 

c

If the dipole is rotated in the electric field, the maximum potential energy of the dipole is 1.3 J.

d

The potential energy of the dipole is 0.6 J.

answer is A, B, D.

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Detailed Solution

P=(2i+3j)106 and E=(3i+2k)105τ¯=P¯×E¯=(0.6i0.4j0.9k)U=P.E=2×3×101=0.6 JUmax=|P||E|=13×13×101=1.3J

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