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Q.

An electric dipole of dipole moment 6.0×106 Cm is placed in a uniform electric field of 1.5×103NC1 in such a way that dipole moment is along electric field. The work done in rotating dipole by 180° in this field will be ____mJ. 

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answer is 18.

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Detailed Solution

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W=PEcosθ1cosθ2θ1=0,θ2=180W=2PE=2×6×106×1.5×103=18×10-3J=18mJ

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