Q.

An electric dipole of dipole moment 6 × 10–6 cm is placed in uniform electric field of magnitude 106 V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to 
the field, will be _____ J.

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answer is 12.

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Detailed Solution

p=6×106CmE=106v/mW=ΔU=pEcosθfcosθiW=2pE=12J

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