An electric dipole of moment 5 ×10–8 C-m is aligned in a uniform electric field of 1.44 ×104N/C.potential energy of the dipole to hold the dipole at 60° with the direction of electric field in (10–4) J.

Potential energy =pEcos⁡θ1−cos⁡θ2=−7.2×10−4(0.5−1)=3.6×10−4J

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An electric dipole of moment 5 ×10^–8 C-m is aligned in a uniform electric field of 1.44 ×10⁴N/C.potential energy of the dipole to hold the dipole at 60° with the direction of electric field in (10^–4) J.

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answer is 3.6.

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Potential energy $= pE (\cos θ_{1} - \cos θ_{2})$

$= - 7.2 \times 10^{- 4} (0.5 - 1) = 3.6 \times 10^{- 4} J$

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