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Q.

An electric dipole of moment ‘p’ is placed normal to the lines of force of a uniform electric intensity E, then the work done in deflecting it through an angle of 180° is

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a

zero

b

-2pE

c

pE

d

+2pE

answer is D.

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Detailed Solution

Here,

θ1=90o θ2=90o+180o =270o

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Work done is change in potential energy of the dipole

=∫θ1=90θ2=270pE sinθ dθ =[-pE cosθ]90270 =0

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