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Q.

An electric dipole of moment  p=i^3j^+2k^×1029Cm is at the origin 0,0,0 . The electric field due to the dipole at r=+i^+3j^+5k^  is parallel to:

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a

+i^3j^2k^

b

+i^+3j^2k^

c

i^3j^+2k^

d

i^+3j^2k^

answer is D.

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Detailed Solution

r.p=+i^+3j^+5k^.i^3j^+2k^×1029=0 So , r and p are perpendicular to each other.Hence, the point is on perpendicular bisector of dipole, where E is anti parallel to P.E is along +i^+3j^2k^

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