An electric dipole of moment $\overrightarrow{\mathrm{P}}=\left(-\widehat{\mathrm{i}}-3\widehat{\mathrm{j}}+2\widehat{\mathrm{k}}\right)\times {10}^{-29} \mathrm{Cm}$  is at the origin $\left(0,0,0\right)$ . The electric field due to this dipole at $\overrightarrow{\mathrm{r}}=+\widehat{\mathrm{i}}+3\widehat{\mathrm{j}}+5\widehat{\mathrm{k}} \left(\mathrm{note}\overrightarrow{\mathrm{r}}.\overrightarrow{\mathrm{p}}=\overrightarrow{0}\right)$  is parallel to:

Since $\overrightarrow{r}$ and $\overrightarrow{p}$ are perpendicular to each other, therefore point lies on the equatorial plane. Therefore, electric field at the point will be anti-parallel to the dipole moment.

$\Rightarrow \hat{\mathrm{E}}=-\hat{\mathrm{p}}$