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An electric dipole with dipole moment P is placed with its axis at $30^{0}$ to a uniform electric filed of intensity (E). The work done by external agent in rotating the dipole to a position where its axis is perpendicular to the field is

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2 pE

$\frac{2pE}{\sqrt{3}}$

$\frac{\sqrt{3} pE}{2}$

$\frac{p E}{2}$

answer is C.

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Detailed Solution

$W = pE (c o s θ_{1} - c o s θ_{2})$

$= pE (c o s 30^{0} - c o s 90^{0})$

$= pE (\frac{\sqrt{3}}{2} - 0) = \frac{\sqrt{3}}{2} pE$

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