An electric field at (x,y )is given by $\overrightarrow{\mathrm{E}}=(\mathrm{y}\hat{\mathrm{i}}+\mathrm{x}\hat{\mathrm{j}}) {\mathrm{NC}}^{-1}$. The work done $\left(\mathrm{in} \mathrm{J}\right)$ by the electric field in moving a $1 \mathrm{C}$ charge from is $\overrightarrow{{\mathrm{r}}_{\mathrm{A}}}=(2\hat{\mathrm{i}}+2\hat{\mathrm{j}}) \mathrm{m}\text{ to }\overrightarrow{{\mathrm{r}}_{\mathrm{B}}}=(4\hat{\mathrm{i}}+\hat{\mathrm{j}}) \mathrm{m}$ is