An electric field of 1000 V/m is applied to an electric dipole at angle of 45∘. The value of electric dipole moment is 10-29Cm. What is the potential energy of the electric dipole ?

U=−p→⋅E→=−pEcos⁡45∘=−10−29×103×12U=−7×10−27J

An electric field of 1000 V/m is applied to an electric dipole at angle of 45∘. The value of electric dipole moment is 10-29Cm. What is the potential energy of the electric dipole ?

U=−p→⋅E→=−pEcos⁡45∘=−10−29×103×12U=−7×10−27J

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An electric field of 1000 V/m is applied to an electric dipole at angle of $45^{\circ}$ . The value of electric dipole moment is $10^{- 29} C m$ . What is the potential energy of the electric dipole ?

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$- 9 \times 10^{- 20} J$

$- 10 \times 10^{- 29} J$

$- 7 \times 10^{- 27} J$

$- 20 \times 10^{- 18} J$

answer is C.

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Detailed Solution

$U = - \vec{p} \cdot \vec{E}$

$= - p E \cos 45^{\circ}$

$= - 10^{- 29} \times 10^{3} \times \frac{1}{\sqrt{2}}$

$U = - 7 \times 10^{- 27} J$

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An electric field of 1000 V/m is applied to an electric dipole at angle of 45∘. The value of electric dipole moment is 10-29Cm. What is the potential energy of the electric dipole ?

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An electric field of 1000 V/m is applied to an electric dipole at angle of $45^{\circ}$ . The value of electric dipole moment is $10^{- 29} C m$ . What is the potential energy of the electric dipole ?