An electric iron consumes 1 kW of electric power when operated at 220 V. Which among the following rate of fuse should be used?

The fuse to be used can be determined by dividing the power used by the appliance by the voltage going into the appliance. Here, 

Power = 1 kW = 1000 W

Voltage = 220 V

Therefore, Current = $\frac{1000}{220}$

                                  = 4.54 

                                  $\approx$5 A