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An electric lamp of resistance $20 Ω$ and a conductor of resistance $4 Ω$ are connected to a $6 V$ battery as shown in the circuit given below.

Calculate the current through the circuit.

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0.25 A

0.5 A

1 A

0.125 A

answer is A.

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Detailed Solution

An electric lamp of resistance

20 Ω

and a conductor of resistance

4 Ω

are connected to a

6 V

battery. The current through of the circuit is

0.25 A

.
We can say that the total resistance in series resistance is the sum of all the resistances that are connected in series.
This gives,

R = 20 + 4

\Rightarrow

R = 24 ohm

So, the current through the circuit is

I = V / R

based on ohm’s law.
Here,

V

is the voltage and

R

is the resistance

\Rightarrow I = 6 / 24 A

\Rightarrow I = 0.25 A

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