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Q.

An electric pump on the ground floor of a building takes 10 min to fill a tank of volume 30 m3 with water. If the tank is 60 m above the ground and the efficiency of the pump is 30% then how much electric power is consumed by the pump in filling the tank? Take g = 10m/ s2 (in Kw)

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Detailed Solution

Total mass of water to be lifted up is,
m=30m3×1000kg/m3=3×104kg
Work done against gravity to lift this much water to a height of 60 m
W=mg×h=3×104×10×60=1.8×107J
Work done by pump is, W1=W0.3=6×107J
Required power of pump is,
P=W1t=6×107600W=100KW

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