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An electrical bulb rated 220 V, 100 W, is connected in series with another bulb rated 220 V, 60 W. If the voltage across combination is 220 V, the power consumed by the 100 W bulb will be..... W (round off to nearest integer) .

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answer is 14.

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Detailed Solution

$R_{1} = \frac{V^{2}}{P} = \frac{220^{2}}{100} = 484 R_{2} = \frac{V^{2}}{P} = \frac{220^{2}}{60} = 484 (\frac{10}{6}) I = \frac{220}{484 + 484 \times \frac{10}{6}} P_{1} = I^{2} R_{1} = 14.06 W$

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