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Q.

An electrical shopkeeper purchases bulbs from three manufacturers A, B, C. He purchases 25% of his stock from A, 45% from B and 30% from C. In the past purchases he found 2% of C’s bulbs, 1% of B’s bulbs, 1% of A’s bulbs were defective. Assuming that, the shopkeeper choose a bulb and found it to be defective

 Column – I  Column – II
(A)The probability of choosing A and purchasing a defective bulb from it is (1)0.0025
(B)The probability of choosing B and purchasing a Defective bulb from it is (2)0.0045
(C)The probability of choosing C and purchasing a Defective bulb from it is (3)0.0060
(D)The probability that the defective bulb was purchased from C is  (4)0.65
  (5)0.46

The correct match from List – I with List – II is 

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a

A – 4; B – 5; C – 2; D – 3  

b

A – 5; B – 2; C – 3; D – 1  

c

A – 2; B – 3; C – 1; D – 5

d

A – 1; B – 2; C – 3; D – 5

answer is D.

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Detailed Solution

P(A)=25100,     P(B)=45100,  P(C)  =30100       P(EC)=2100,     P(EB)=1100,  P(EA)  =1100      

A)  P(AE)=P(A).  P(EA)=2510000=0.0025
B)  P(BE)=0.0045
C) P(CE)=0.0060
D) Required probability = 0.46

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