AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

An electrician has to repair an electric fault on a pole of height $5$ m. She needs to reach a point $1.3$ m below the top of the pole to undertake the repair work. What should be the length of the ladder that she should use which, when inclined at an angle of $60^{0}$ to the horizontal, would enable her to reach the required position? Also, how far from the foot of the pole should she place the foot of the ladder? ( You may take $\sqrt{3} = 1.73$ ).

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

length of ladder = 7.4 m

distance = 2.14 m

length of ladder = 4.27 m

distance = 3.7 m

length of ladder = 4.27 m

distance = 2.14 m

length of ladder = 4.7 m

distance = 2.14 m

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

It is given that the height of the

5

m and the angle of inclination is

60^{0}

to the horizontal
We have to find how far from the foot of the pole she should place the foot of the ladder.
Question Image

We use the identities,

sinθ = \frac{perpendicular}{hypotenuse},

tanθ = \frac{perpendicular}{b ase} .

Applying the above concept,
We get,

\sin 60 ° = \frac{BC}{BD}

\Rightarrow \frac{\sqrt{3}}{2} = \frac{3.7}{l}

[since

\sin 60 ° = \frac{\sqrt{3}}{2}

]

\Rightarrow l = \frac{2 (3.7)}{\sqrt{3}}

\Rightarrow l = 4.27 m

Now, by applying another identity,

\tan 60 ° = \frac{BC}{CD}

\Rightarrow \sqrt{3} = \frac{3.7}{x}

[since

\tan 60 ° = \sqrt{3}

]

\Rightarrow x = \frac{3.7}{\sqrt{3}}

\Rightarrow x = 2.138

\Rightarrow x \approx 2.14 m .

Hence, the length of the ladder is 4.27m and it is 2.14 m far from the foot of the pole should she place the foot of the ladder.
Therefore, the correct option is 3.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!