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Q.

An electrician has to repair an electric fault on a pole of height 5m. She needs to reach a point 1.3m below the top of the pole to undertake the repair work. What should be the length of the ladder that she should use which, when inclined at an angle of 600to the horizontal, would enable her to reach the required position? Also, how far from the foot of the pole should she place the foot of the ladder? ( You may take 3=1.73).


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a

length of ladder=7.4m, distance=2.14m

b

length of ladder=4.27m, distance=3.7m

c

length of ladder=4.27m, distance=2.14m

d

length of ladder=4.7m, distance=2.14m  

answer is C.

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Detailed Solution

It is given that the height of the 5m and the angle of inclination is 600to the horizontal
We have to find how far from the foot of the pole she should place the foot of the ladder.
Question ImageWe use the identities,
sinθ=perpendicularhypotenuse,  tanθ=perpendicularbase.
Applying the above concept,
We get,
sin 60°=BCBD 32=3.7l  [since sin 60°=32]
l=2(3.7)3
l=4.27m Now, by applying another identity,
tan 60°=BCCD 3=3.7x   [since tan 60°=3]
x=3.73
x=2.138 x2.14m.
Hence, the length of the ladder is 4.27m and it is 2.14 m  far from the foot of the pole should she place the foot of the ladder.
Therefore, the correct option is 3.
 
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