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An electromagnetic wave going through vacuum is described by $E = E_{0} \sin (k x - ω t)$ ; $B = B_{0} \sin (k x - ω t)$ . Which of the following equation is true.

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$E_{0} k = B_{0} ω$

$E_{0} ω = B_{0} k$

$E_{0} B_{0} = ω k$

$E B = ω k$

answer is A.

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Detailed Solution

$\frac{E_{0}}{B_{0}} = C .$ .....(1)

also $k = \frac{2 π}{λ}$ and $ω = 2 π ν$ .

$\Rightarrow k = \frac{2 π ν}{C} = \frac{ω}{C}$ .....(2)

from equations (1) and (2),

$E_{0} k = B_{0} ω$

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