An Electromagnetic wave is propagating in x direction. Magnetic field in space is given by B→=2×10−8k^T. What will be the value and direction of electric field (in Vm-1)?

E^=B^×v^=k^×i^=j^E=Bc=2×10-8×3×108=6 Vm-1

An Electromagnetic wave is propagating in x direction. Magnetic field in space is given by B→=2×10−8k^T. What will be the value and direction of electric field (in Vm-1)?

E^=B^×v^=k^×i^=j^E=Bc=2×10-8×3×108=6 Vm-1

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An Electromagnetic wave is propagating in x direction. Magnetic field in space is given by $\vec{B} = 2 \times 10^{- 8} \hat{k} T$ . What will be the value and direction of electric field (in $V m^{- 1}$ )?

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$0.6 \hat{j}$

$6 \hat{j}$

$0.6 \hat{k}$

$6 \hat{k}$

answer is B.

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Detailed Solution

$\hat{E} = \hat{B} \times \hat{v} = \hat{k} \times \hat{i} = \hat{j}$

$E = B c = 2 \times 10^{- 8} \times 3 \times 10^{8} = 6 V m^{- 1}$

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An Electromagnetic wave is propagating in x direction. Magnetic field in space is given by B→=2×10−8k^T. What will be the value and direction of electric field (in Vm-1)?

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An Electromagnetic wave is propagating in x direction. Magnetic field in space is given by $\vec{B} = 2 \times 10^{- 8} \hat{k} T$ . What will be the value and direction of electric field (in $V m^{- 1}$ )?