An electromagnetic wave of frequency 3 MHz passes from Vacuum into a dielectric medium with relative permittivity $ϵ_{r} = 4 .0$ Then

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wave length is doubled and frequency becomes half

wave length and frequency both remain unchanged

wave length is halved and frequency remains unchanged

wave length doubled and frequency remains unchanged

answer is C.

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Detailed Solution

$\begin{aligned} v_{med} = \frac{1}{\sqrt{μ_{0} ϵ_{0} \times 4}} = \frac{c}{2} \\ \frac{λ_{med}}{λ_{air}} = \frac{V_{med}}{V_{air}} = \frac{\frac{c}{2}}{c} = \frac{1}{2} \end{aligned}$

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