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An electron accelerated through a potential difference V passes through a uniform transverse magnetic field and experiences a force F. If the accelerating potential is increased to 2V, the electron in the same magnetic field will experience a force

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F/2

$\sqrt{2} F$

answer is C.

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Detailed Solution

$F = B q v$

But $\frac{1}{2} m v^{2} = e V$ or $v = \sqrt{\frac{2 e V}{m}}$

$∴ F = B q \sqrt{\frac{2 e V}{m}}$

$\Rightarrow$ $F \propto \sqrt{V}$ and

$F' \propto \sqrt{2 V}$

$\frac{F'}{F} = \sqrt{2}$ and $F' = \sqrt{2} F$

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