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An electron and a photon have same wavelength. If P is the momentum of electron and E is the energy of photon. The magnitude of P/E in SI unit is

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3x10⁸

3.33x10^-9

9.1x10^-31

6.64x10^-34

answer is B.

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Detailed Solution

$λ = \frac{h}{p} (electron)$

$or P = \frac{h}{λ}$
$and E = \frac{h c}{λ} (photon)$
$\frac{P}{E} = \frac{1}{C} = 3.33 \times 10^{- 9}$

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