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An electron and a proton start moving parallel between the plates (one negative and other positively charged) towards the other end from the mid-point of the separation of plates at one end of the plates. Which of the two will have greater deviation when they come out of the plates if they start with the same initial momentum

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deviation of electron is more

both deviates equally

deviation of proton is less

deviation of proton is more

answer is B.

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Detailed Solution

$Time after charged particle ejected from the plates$

$t = \frac{ℓ}{u}$

$Hence deviation y = \frac{1}{2} a_{y} t^{2} = \frac{1}{2} \frac{q E}{m} {(\frac{ℓ}{u})}^{2} = \frac{q E ℓ^{2}}{2 p^{2}} \cdot m$

here, momentum is $p$ .

$Since m_{p} > m_{e}$

$\Rightarrow y_{p} > y_{e} electron deviation would be greater compared to proton.$

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