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Q.

An electron beam travels with a velocity of 1.6 x 107ms–1 perpendicular to magnetic field of intensity 0.1 T. The radius of the path of the election beam
(me=9 x 10–31kg)

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a

9 x 10–4 m

b

9 x 10–3 m

c

9 x 10–2 m

d

9 x 10–5 m

answer is C.

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Detailed Solution

r = mvqB= 9×10-4m

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